Probably common sense, but this statistically supports the most common roll of the dice. Of course, this assumes physical normalcy of the die, not loaded, etc. 🙂
[root@cmhlcanlyodb01 ~]# cat rand.py import random d = dict() for i in range(1,100001): j=random.randint(1,6) k=random.randint(1,6) l=j+k if l in d: d[l] = d[l] + 1 else: d[l] = 1 for a in d: print str(a).rjust(10,' '),str(d[a]).rjust(10,' '), str(round(float(d[a])*100/float(100001),1)).rjust(10,' ') [root@cmhlcanlyodb01 ~]# python rand.py 2 2739 2.7 3 5568 5.6 4 8320 8.3 5 11355 11.4 6 13765 13.8 7 16830 16.8 8 13695 13.7 9 10991 11.0 10 8269 8.3 11 5687 5.7 12 2781 2.8 [root@cmhlcanlyodb01 ~]#